tensorflow::ops::UniqueWithCounts
tensorflow::ops::UniqueWithCounts
#include <array_ops.h>
Finds unique elements in a 1-D tensor.
Summary
This operation returns a tensor y
containing all of the unique elements of x
sorted in the same order that they occur in x
. This operation also returns a tensor idx
the same size as x
that contains the index of each value of x
in the unique output y
. Finally, it returns a third tensor count
that contains the count of each element of y
in x
. In other words:
y[idx[i]] = x[i] for i in [0, 1,...,rank(x) - 1]
For example:
``` tensor 'x' is [1, 1, 2, 4, 4, 4, 7, 8, 8]
y, idx, count = unique_with_counts(x) y ==> [1, 2, 4, 7, 8] idx ==> [0, 0, 1, 2, 2, 2, 3, 4, 4] count ==> [2, 1, 3, 1, 2] ```
Arguments:
- scope: A 登录查看完整内容