ufunc.reduce()

numpy.ufunc.reduce

ufunc.reduce(a, axis=0, dtype=None, out=None, keepdims=False)

Reduces a‘s dimension by one, by applying ufunc along one axis.

Let $a.shape = (N_0, ..., N_i, ..., N_{M-1})$ . Then $ufunc.reduce(a, axis=i)[k_0, ..,k_{i-1}, k_{i+1}, .., k_{M-1}]$ = the result of iterating j over $range(N_i)$ , cumula

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