Numpy 1.11
Numpy 1.11
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numpy.outer()

numpy.outer

numpy.outer(a, b, out=None) [source]

Compute the outer product of two vectors.

Given two vectors, a = [a0, a1, ..., aM] and b = [b0, b1, ..., bN], the outer product [R55] is:

[[a0*b0  a0*b1 ... a0*bN ]
 [a1*b0    .
 [ ...          .
 [aM*b0            aM*bN ]]
Parameters:

a : (M,) array_like

First input vector. Input is flattened if