numpy.linalg.inv(a)
Compute the (multiplicative) inverse of a matrix.
Given a square matrix a, return the matrix ainv satisfying dot(a, ainv) = dot(ainv, a) = eye(a.shape[0]).
a
ainv
dot(a, ainv) = dot(ainv, a) = eye(a.shape[0])
a : (..., M, M) array_like
Matrix to be inverted.
ainv : (
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