numpy.sqrt()

numpy.sqrt

numpy.sqrt(x[, out]) =

Return the positive square-root of an array, element-wise.

Parameters:

Parameters:	x : array_like The values whose square-roots are required. out : ndarray, optional Alternate array object in which to put the result; if provided, it must have the same shape as `x`
Returns:	y : ndarray An array of the same shape as `x`, containing the positive square-root of each element in `x`. If any element in `x` is complex, a complex arr 登录查看完整内容 ← → Copyright©2021 w3cschool编程狮\|闽ICP备15016281号-3\|闽公网安备35020302033924号违法和不良信息举报电话：173-0602-2364\|举报邮箱：jubao@eeedong.com 意见反馈 X 意见反馈：联系方式：查看完整版笔记违规举报 X 广告等垃圾信息不友善内容违反法律法规的内容不宜公开讨论的政治内容其他

x : array_like

The values whose square-roots are required.

out : ndarray, optional

Alternate array object in which to put the result; if provided, it must have the same shape as x

Returns:

y : ndarray

An array of the same shape as x, containing the positive square-root of each element in x. If any element in x is complex, a complex arr