Pandas 0.18
Pandas 0.18
  • 请登录查看
字典 我要纠错

TimedeltaIndex.transpose()

pandas.TimedeltaIndex.transpose

TimedeltaIndex.transpose(*args, **kwargs)

return the transpose, which is by definition self

© 2011–2012 Lambda Foundry, Inc. and PyData Development Team
© 2008–2011 AQR Capital Management, LLC
© 2008–2014 the pandas development team
Licensed under the 3-clause BSD License.
http://pandas.pydata.org/pandas-docs/version/0.18.1/generated/pandas.TimedeltaIndex.transpose.html